Dual Nature of Radiation and Matter is a Class 12 Physics chapter that carries about 4.4% of the Physics questions in NEET. Practise it with 45 questions covering 2 topics, each with an explanation.
Sample questions on Dual Nature of Radiation and Matter with answers
8 questions from the practice bank, spread across the chapter's topics. The full set is in the app.
Question 1: Photoelectric Effect
If the intensity of light above the threshold frequency is increased, the photoelectric current:
- A stays the same, and the kinetic energy increases
- B increases, but the maximum kinetic energy of electrons is unchanged
- C stays the same
- D decreases
Answer: B. increases, but the maximum kinetic energy of electrons is unchanged
Why: More photons per second free more electrons, but the energy of each photon, and so K_max, depends only on the frequency.
Question 2: de Broglie Wavelength
The wave nature of matter, as proposed by de Broglie, is most easily observed for:
- A macroscopic objects like a cricket ball
- B microscopic particles like electrons
- C objects at rest only
- D objects with zero mass only
Answer: B. microscopic particles like electrons
Why: Since de Broglie wavelength λ=h/p is inversely proportional to momentum, it becomes significant only for very light, fast-moving particles like electrons — for macroscopic objects it's immeasurably small.
Question 3: Photoelectric Effect
In the photoelectric effect, the maximum kinetic energy of the emitted electrons depends on:
- A the intensity of the incident light only
- B the frequency of the incident light
- C both intensity and frequency equally
- D the area of the illuminated metal surface
Answer: B. the frequency of the incident light
Why: KE_max = hν − φ. Maximum kinetic energy depends on the frequency of light (and the work function), not on intensity.
Question 4: de Broglie Wavelength
The de Broglie wavelength of a moving particle is given by:
- A λ = h/p (Planck's constant / momentum)
- B λ = hp
- C λ = p/h
- D λ = h × p²
Answer: A. λ = h/p (Planck's constant / momentum)
Why: de Broglie proposed that every moving particle has an associated wavelength λ = h/p, where p is its momentum.
Question 5: Photoelectric Effect
Light of photon energy 5 eV falls on a metal of work function 2 eV. The maximum kinetic energy of the emitted electrons is:
- A 3 eV
- B 2.5 eV
- C 10 eV
- D 7 eV
Answer: A. 3 eV
Why: Einstein's equation: K_max = hν − φ = 5 − 2 = 3 eV.
Question 6: de Broglie Wavelength
In the Davisson–Germer experiment, electrons accelerated through 54 V were diffracted. Their de Broglie wavelength was about:
- A 0.167 Å
- B 16.7 Å
- C 5.4 Å
- D 1.67 Å
Answer: D. 1.67 Å
Why: λ = 12.27/√54 ≈ 1.67 Å, which matched the spacing of nickel atoms.
Question 7: Photoelectric Effect
The energy of a photon of wavelength 620 nm is about (hc = 1240 eV nm):
- A 20 eV
- B 6.2 eV
- C 2 eV
- D 0.5 eV
Answer: C. 2 eV
Why: E = hc/λ = 1240/620 = 2 eV.
Question 8: de Broglie Wavelength
Photoelectrons of maximum kinetic energy 4 eV are emitted. The de Broglie wavelength of the fastest electron is about:
- A 0.6 Å
- B 6.1 Å
- C 12 Å
- D 1.2 Å
Answer: B. 6.1 Å
Why: λ = 12.27/√4 = 6.1 Å.