The NEET 2020 paper had 180 questions across Biology, Physics and Chemistry, marked +4 for a correct answer and −1 for a wrong one. This page shows what it contained, which chapters it drew on, and 10 of its questions with answers.
Sample questions from NEET 2020 with answers
A spread of 10 questions from the paper, chosen across the three subjects. The full paper is in the app.
Question 21
Biology · Biotechnology: Principles and ProcessesThe specific palindromic sequence which is recognized by EcoRI is
- A 5′-GAATTC-3′ / 3′-CTTAAG-5′
- B 5′-GGAACC-3′ / 3′-CCTTGG-5′
- C 5′-CTTAAG-3′ / 3′-GAATTC-5′
- D 5′-GGATCC-3′ / 3′-CCTAGG-5′
Answer: A. 5′-GAATTC-3′ / 3′-CTTAAG-5′
Why: EcoRI recognises the palindrome 5′-GAATTC-3′ (reads the same 5′→3′ on both strands) and cuts between G and A. GGATCC is the BamHI site.
Question 22
Biology · Biotechnology: Principles and ProcessesIdentify the wrong statement with regard to Restriction Enzymes.
- A Each restriction enzyme functions by inspecting the length of a DNA sequence.
- B They cut the strand of DNA at palindromic sites.
- C They are useful in genetic engineering.
- D Sticky ends can be joined by using DNA ligases.
Answer: D. Sticky ends can be joined by using DNA ligases.
Why: The official NTA final key is option 4. Note: by NCERT, sticky ends are joined by DNA ligase, so option 4 reads as a correct statement and this question is generally regarded as debatable; the key is kept as official.
Question 50
Biology · BiomoleculesFloridean starch has structure similar to
- A Starch and cellulose
- B Amylopectin and glycogen
- C Mannitol and algin
- D Laminarin and cellulose
Answer: B. Amylopectin and glycogen
Why: Floridean starch, the food reserve of red algae, is highly branched like amylopectin and glycogen, so option 2.
Question 54
Biology · Human ReproductionWhich of the following hormone levels will cause release of ovum (ovulation) from the graffian follicle?
- A High concentration of Estrogen
- B High concentration of Progesterone
- C Low concentration of LH
- D Low concentration of FSH
Answer: A. High concentration of Estrogen
Why: Rising estrogen from the mature follicle triggers a mid-cycle LH surge that causes the Graafian follicle to rupture and release the ovum, so high estrogen (option 1).
Question 83
Biology · Principles of Inheritance and VariationExperimental verification of the chromosomal theory of inheritance was done by
- A Mendel
- B Sutton
- C Boveri
- D Morgan
Answer: D. Morgan
Why: Sutton and Boveri proposed the chromosomal theory, but Thomas Hunt Morgan verified it experimentally with his Drosophila work on linkage and sex-linked inheritance.
Question 112
Chemistry · General Principles of Organic ChemistryA tertiary butyl carbocation is more stable than a secondary butyl carbocation because of ?
- A – I effect of – CH₃ groups
- B + R effect of – CH₃ groups
- C – R effect of – CH₃ groups
- D Hyperconjugation
Answer: D. Hyperconjugation
Why: The tertiary cation has more α C–H bonds (9 versus 5) available for hyperconjugation with the empty p orbital, which stabilises it more. Answer: option 4.
Question 116
Chemistry · Coordination CompoundsWhich of the following is the correct order of increasing field strength of ligands to form coordination compounds?
- A SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻
- B SCN⁻ < F⁻ < CN⁻ < C₂O₄²⁻
- C F⁻ < SCN⁻ < C₂O₄²⁻ < CN⁻
- D CN⁻ < C₂O₄²⁻ < SCN⁻ < F⁻
Answer: A. SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻
Why: In the spectrochemical series the order is SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻ (cyanide being a very strong field ligand). Answer: option 1.
Question 123
Chemistry · Some Basic Concepts of ChemistryWhich one of the followings has maximum number of atoms ?
- A 1 g of Ag(s) [Atomic mass of Ag = 108]
- B 1 g of Mg(s) [Atomic mass of Mg = 24]
- C 1 g of O₂(g) [Atomic mass of O = 16]
- D 1 g of Li(s) [Atomic mass of Li = 7]
Answer: D. 1 g of Li(s) [Atomic mass of Li = 7]
Why: For equal mass the number of atoms is mass/atomic mass × Nₐ (×2 for O₂ molecules); 1 g Li gives 1/7 mol of atoms, more than Ag (1/108), Mg (1/24) or O (1/16), so option 4.
Question 173
Physics · Current ElectricityA charged particle having drift velocity of 7.5 × 10⁻⁴ m s⁻¹ in an electric field of 3 × 10⁻¹⁰ V m⁻¹, has a mobility in m² V⁻¹ s⁻¹ of :
- A 2.25 × 10¹⁵
- B 2.5 × 10⁶
- C 2.5 × 10⁻⁶
- D 2.25 × 10⁻¹⁵
Answer: B. 2.5 × 10⁶
Why: Mobility μ = v_d/E = 7.5 × 10⁻⁴ / 3 × 10⁻¹⁰ = 2.5 × 10⁶ m² V⁻¹ s⁻¹.
Question 178
Physics · Mechanical Properties of FluidsA capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is :
- A 2.5 g
- B 5.0 g
- C 10.0 g
- D 20.0 g
Answer: C. 10.0 g
Why: Height h ∝ 1/r, mass = ρπr²h ∝ r. Doubling the radius doubles the mass to 10 g (equivalently, the supported weight equals the surface-tension force 2πrT cosθ, which is proportional to r).