System of Particles and Rotational Motion is a Class 11 Physics chapter that carries about 4.7% of the Physics questions in NEET. Practise it with 48 questions covering 2 topics, each with an explanation.
Sets of 15 questions that adapt to your level, with an explanation for every answer.
Across the 13 previous year papers, System of Particles and Rotational Motion had 30 questions, about 2.3 a year. The most in one paper was 4, in NEET 2018.
| Paper | Questions from this chapter |
|---|---|
| NEET 2026 | 2 |
| NEET 2025 | 3 |
| NEET 2024 | 2 |
| NEET 2023 | 0 |
| NEET 2022 | 3 |
| NEET 2021 | 2 |
| NEET 2020 | 2 |
| NEET 2019 | 1 |
| NEET 2018 | 4 |
| NEET 2017 | 3 |
| NEET 2016 | 3 |
| Re-AIPMT 2015 | 3 |
| AIPMT 2014 | 2 |
8 questions from the practice bank, spread across the chapter's topics. The full set is in the app.
A shell moving in a parabolic path explodes in mid-air. The centre of mass of the fragments:
Answer: D. continues to follow the original parabolic path
Why: The explosion is caused by internal forces, which cannot change the motion of the centre of mass.
A force of 5 N acts at the end of a spanner of length 0.4 m, perpendicular to it. The torque produced is:
Answer: B. 2 N m
Why: τ = rF sin90° = 0.4 × 5 = 2 N m.
A solid cylinder rolls without slipping. The fraction of its total kinetic energy that is rotational is:
Answer: B. 1/3
Why: K_rot = ½ × ½MR²ω² = ¼Mv², K_trans = ½Mv², so K_rot/K = 1/3.
Two equal and opposite forces of 5 N act on a body, separated by a perpendicular distance of 0.4 m. The torque of this couple is:
Answer: B. 2 N m
Why: τ = F × d = 5 × 0.4 = 2 N m.
The moment of inertia of a rod of mass M and length L about an axis through its centre and perpendicular to its length is ML²/12. About a parallel axis through one end it is:
Answer: D. ML²/3
Why: By the parallel axis theorem, I = ML²/12 + M(L/2)² = ML²/12 + ML²/4 = ML²/3.
A 30 kg child sits 2 m from the pivot of a see-saw. A 20 kg child balances it by sitting on the other side at a distance of:
Answer: A. 3 m
Why: 30 × 2 = 20 × x gives x = 3 m.
The moment of inertia of a uniform solid sphere about an axis through its center (diameter) is:
Answer: A. (2/5)MR²
Why: The moment of inertia of a uniform solid sphere about its diameter is I = (2/5)MR².
The torque of a force about an axis passing through its point of application is:
Answer: A. zero
Why: The perpendicular distance from the axis to the line of action is zero.
System of Particles and Rotational Motion carries about 4.7% of the Physics questions in NEET. Across the 13 previous year papers on NeetVictory it appeared 30 times, about 2.3 questions a year.
System of Particles and Rotational Motion is a Class 11 Physics chapter in the NCERT syllabus.
NeetVictory has 48 practice questions on System of Particles and Rotational Motion, each with an explanation, in sets of 15 that adapt to your level. This page shows a free sample.
NeetVictory