The Re-AIPMT 2015 paper had 180 questions across Biology, Physics and Chemistry, marked +4 for a correct answer and −1 for a wrong one. This page shows what it contained, which chapters it drew on, and 10 of its questions with answers.
Sample questions from Re-AIPMT 2015 with answers
A spread of 10 questions from the paper, chosen across the three subjects. The full paper is in the app.
Question 12
Chemistry · Some Basic Concepts of ChemistryThe number of water molecules is maximum in
- A 18 gram of water
- B 18 moles of water
- C 18 molecules of water
- D 1.8 gram of water
Answer: B. 18 moles of water
Why: 18 moles contain 18 × 6.022×10²³ molecules, far more than 1 mole (18 g), 0.1 mole (1.8 g) or 18 molecules.
Question 18
Chemistry · p-Block ElementsWhich of the statements given below is incorrect?
- A ONF is isoelectronic with O₂N⁻
- B OF₂ is an oxide of fluorine
- C Cl₂O₇ is an anhydride of perchloric acid
- D O₃ molecule is bent
Answer: B. OF₂ is an oxide of fluorine
Why: OF₂ is a fluoride of oxygen (oxygen is the less electronegative element), not an oxide of fluorine, so statement (2) is incorrect.
Question 26
Chemistry · SolutionsWhat is the mole fraction of the solute in a 1.00 m aqueous solution?
- A 0.0354
- B 0.0177
- C 0.177
- D 1.770
Answer: B. 0.0177
Why: 1 m means 1 mol solute in 1000 g (55.5 mol) water, so x = 1/(1 + 55.5) ≈ 0.0177.
Question 75
Biology · Structural Organisation in AnimalsThe function of the gap junction is to :
- A Stop substance from leaking across a tissue.
- B Performing cementing to keep neighbouring cells together.
- C Facilitate communication between adjoining cells by connecting the cytoplasm for rapid transfer of ions, small molecules and some large molecules.
- D Separate two cells from each other.
Answer: C. Facilitate communication between adjoining cells by connecting the cytoplasm for rapid transfer of ions, small molecules and some large molecules.
Why: Gap junctions form channels linking the cytoplasm of adjacent cells, allowing rapid passage of ions and small molecules. Tight junctions prevent leakage and adhering junctions cement cells.
Question 97
Biology · Strategies for Enhancement in Food ProductionOutbreeding is an important strategy of animal husbandry because it:
- A Exposes harmful recessive genes that are eliminated by selection.
- B Helps in accumulation of superior genes.
- C Is useful in producing purelines of animals.
- D Is useful in overcoming inbreeding depression.
Answer: D. Is useful in overcoming inbreeding depression.
Why: Mating unrelated animals (outcrossing) restores fertility and productivity lost through continued inbreeding, i.e. it overcomes inbreeding depression.
Question 100
Biology · Biological ClassificationThe structures that help some bacteria to attach to rocks and /or host tissues are :
- A Holdfast
- B Rhizoids
- C Fimbriae
- D Mesosomes
Answer: C. Fimbriae
Why: Fimbriae are small bristle-like fibres on the bacterial cell surface that help in attachment to rocks and host tissues.
Question 109
Biology · Biological ClassificationThe imperfect fungi which are decomposers of litter and help in mineral cycling belong to:
- A Ascomycetes
- B Deuteromycetes
- C Basidiomycetes
- D Phycomycetes
Answer: B. Deuteromycetes
Why: Fungi whose sexual stage is unknown are called imperfect fungi and placed in Deuteromycetes; many act as litter decomposers and aid mineral cycling.
Question 125
Biology · Breathing and Exchange of GasesName the pulmonary disease in which alveolar surface area involved in gas exchange is drastically reduced due to damage in the alveolar walls.
- A Asthma
- B Pleurisy
- C Emphysema
- D Pneumonia
Answer: C. Emphysema
Why: Emphysema is a chronic disorder in which alveolar walls are damaged (often by smoking), reducing the respiratory surface area for gas exchange.
Question 151
Physics · GravitationA remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25 × 10⁶ m above the surface of earth. If earth's radius is 6.38 × 10⁶ m and g = 9.8 ms⁻², then the orbital speed of the satellite is
- A 6.67 km s⁻¹
- B 7.76 km s⁻¹
- C 8.56 km s⁻¹
- D 9.13 km s⁻¹
Answer: B. 7.76 km s⁻¹
Why: Orbital speed v = √(GM/(R+h)) = R√(g/(R+h)). With R = 6.38×10⁶ m and R+h = 6.63×10⁶ m this gives about 7.76 km/s.
Question 176
Physics · Mechanical Properties of FluidsWater rises to a height h in capillary tube. If the length of capillary tube above the surface of water is made less than h, then
- A Water does not rise at all
- B Water rises upto the tip of capillary tube and then starts overflowing like a fountain
- C Water rises upto the top of capillary tube and stays there without overflowing
- D Water rises upto a point a little below the top and stays there
Answer: C. Water rises upto the top of capillary tube and stays there without overflowing
Why: The meniscus adjusts its radius of curvature (h·r = constant) so that the water column is supported at the shorter height. Water rises to the top and stays without overflowing.