Mechanical Properties of Fluids is a Class 11 Physics chapter that carries about 3.1% of the Physics questions in NEET. Practise it with 43 questions covering 2 topics, each with an explanation.
Sets of 15 questions that adapt to your level, with an explanation for every answer.
Across the 13 previous year papers, Mechanical Properties of Fluids had 18 questions, about 1.4 a year. The most in one paper was 3, in Re-AIPMT 2015.
| Paper | Questions from this chapter |
|---|---|
| NEET 2026 | 1 |
| NEET 2025 | 1 |
| NEET 2024 | 1 |
| NEET 2023 | 2 |
| NEET 2022 | 2 |
| NEET 2021 | 1 |
| NEET 2020 | 1 |
| NEET 2019 | 2 |
| NEET 2018 | 1 |
| NEET 2017 | 1 |
| NEET 2016 | 1 |
| Re-AIPMT 2015 | 3 |
| AIPMT 2014 | 1 |
8 questions from the practice bank, spread across the chapter's topics. The full set is in the app.
A liquid is flowing through a horizontal pipe of constant cross-section. If it is an ideal fluid, the pressure along the pipe:
Answer: B. remains constant
Why: With constant speed and height, Bernoulli's equation gives a constant pressure.
The SI unit of surface tension is:
Answer: D. N/m
Why: Surface tension is force per unit length, or energy per unit area (J/m²).
Water flows horizontally with a speed of 2 m/s in a wide pipe and 4 m/s in a narrow section. The pressure difference between them is (ρ = 1000 kg/m³):
Answer: A. 6000 Pa
Why: ΔP = ½ρ(v₂² − v₁²) = 500 × 12 = 6000 Pa.
The excess pressure inside a water drop of radius 1 mm and surface tension 0.07 N/m is:
Answer: C. 140 Pa
Why: ΔP = 2T/R = 0.14/10⁻³ = 140 Pa.
A hole is made in the side of a tall tank of water at a depth h below the surface, with the tank's height H. The horizontal range of the jet is greatest when h is:
Answer: A. H/2
Why: The range is R = 2√(h(H − h)), which is maximum at h = H/2.
A barometer reads 760 mm of mercury at sea level. This corresponds to a pressure of about:
Answer: A. 1.01 × 10⁵ Pa
Why: P = ρgh = 13 600 × 9.8 × 0.76 ≈ 1.013 × 10⁵ Pa.
Bernoulli's equation expresses the:
Answer: D. conservation of energy for the flow of an ideal fluid
Why: It states P + ½ρv² + ρgh = constant along a streamline.
The work done in blowing a soap bubble of radius 1 cm (T = 0.03 N/m) is about:
Answer: D. 7.5 × 10⁻⁵ J
Why: The bubble has two surfaces: W = T × 2 × 4πR² = 0.03 × 2 × 1.26 × 10⁻³ ≈ 7.5 × 10⁻⁵ J.
Mechanical Properties of Fluids carries about 3.1% of the Physics questions in NEET. Across the 13 previous year papers on NeetVictory it appeared 18 times, about 1.4 questions a year.
Mechanical Properties of Fluids is a Class 11 Physics chapter in the NCERT syllabus.
NeetVictory has 43 practice questions on Mechanical Properties of Fluids, each with an explanation, in sets of 15 that adapt to your level. This page shows a free sample.
NeetVictory