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AIPMT 2014 Question Paper: Chapter-wise Questions and Sample Solutions (Set P)

The AIPMT 2014 paper had 180 questions across Biology, Physics and Chemistry, marked +4 for a correct answer and −1 for a wrong one. This page shows what it contained, which chapters it drew on, and 10 of its questions with answers.

AIPMT 2014 paper at a glance

ExamAIPMT 2014, Set P
Questions180 (90 Biology, 45 Physics, 45 Chemistry)
Duration3 hours
Marking+4 for a correct answer, −1 for a wrong answer
How many to answerAll 180 questions are compulsory.
Sit the full AIPMT 2014 paper

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Which chapters did AIPMT 2014 ask from?

Questions are counted by the chapter they test. The chapters that carried the most were Biological Classification (9), Plant Kingdom (6), Sexual Reproduction in Flowering Plants (5). Use the counts to see where this paper put its weight, and click a chapter for practice questions.

Sample questions from AIPMT 2014 with answers

A spread of 10 questions from the paper, chosen across the three subjects. The full paper is in the app.

Question 1

Physics · Units and Measurements

If force (F), velocity (V) and time (T) are taken as fundamental units, then the dimensions of mass are:-

  1. A [F V T⁻¹]
  2. B [F V T⁻²]
  3. C [F V⁻¹ T⁻¹]
  4. D [F V⁻¹ T]

Answer: D. [F V⁻¹ T]

Why: Force = mass × velocity / time, so mass = F·T/V, giving the dimensions [F V⁻¹ T].

Question 36

Physics · Wave Optics

In the Young's double-slit experiment, the intensity of light at a point on the screen where the path difference is λ is K, (λ being the wave length of light used). The intensity at a point where the path difference is λ/4, will be :-

  1. A K
  2. B K/4
  3. C K/2
  4. D Zero

Answer: C. K/2

Why: I = I_max cos²(φ/2) with I_max = K at path difference λ; at λ/4 the phase is π/2, so I = K cos²(π/4) = K/2.

Question 64

Chemistry · Periodic Classification of Properties

Be²⁺ is isoelectronic with which of the following ions ?

  1. A H⁺
  2. B Li⁺
  3. C Na⁺
  4. D Mg²⁺

Answer: B. Li⁺

Why: Be²⁺ has 4 − 2 = 2 electrons. Li⁺ (3 − 1 = 2 electrons) has the same count, whereas H⁺ has 0 and Na⁺, Mg²⁺ have 10.

Question 75

Chemistry · D and F Block Elements

Reason of lanthanoid contraction is :-

  1. A Negligible screening effect of 'f' orbitals
  2. B Increasing nuclear charge
  3. C Decreasing nuclear charge
  4. D Decreasing screening effect

Answer: A. Negligible screening effect of 'f' orbitals

Why: 4f electrons shield the outer electrons very poorly, so the increasing nuclear charge pulls the outer shell inward across the series, shrinking the radii.

Question 82

Chemistry · Environmental Chemistry

Which of the following is not a common component of Photochemical Smog?

  1. A Ozone
  2. B Acrolein
  3. C Peroxyacetyl nitrate
  4. D Chlorofluorocarbons

Answer: D. Chlorofluorocarbons

Why: Photochemical smog contains ozone, PAN, acrolein, aldehydes and NO₂ formed by sunlight acting on NOx and hydrocarbons; chlorofluorocarbons are ozone-depleting agents, not smog components.

Question 116

Biology · Morphology of Flowering Plants

An aggregate fruit is one which develops from :

  1. A Multicarpellary syncarpous gynoecium
  2. B Multicarpellary apocarpus gynoecium
  3. C Complete inflorescence
  4. D Multicarpellary superior ovary

Answer: B. Multicarpellary apocarpus gynoecium

Why: In aggregate fruits, each free carpel of an apocarpous multicarpellary gynoecium becomes a fruitlet, giving a cluster of fruitlets from one flower (e.g. strawberry, Annona).

Question 128

Biology · Plant Kingdom

An alga which can be employed as food for human being is :-

  1. A Ulothrix
  2. B Chlorella
  3. C Spirogyra
  4. D Polysiphonia

Answer: B. Chlorella

Why: Chlorella is a protein-rich unicellular green alga used as a food supplement (single cell protein), while the other genera are not used as food.

Question 145

Biology · Biomolecules

Which one of the following is a non - reducing carbohydrate ?

  1. A Maltose
  2. B Sucrose
  3. C Lactose
  4. D Ribose 5 - phosphate

Answer: B. Sucrose

Why: In sucrose the anomeric carbons of glucose and fructose are joined by the glycosidic bond, leaving no free aldehyde or ketone group, so it is non-reducing.

Question 162

Biology · Reproductive Health

Tubectomy is a method of sterilization in which :

  1. A small part of the fallopian tube is removed or tied up.
  2. B ovaries are removed surgically.
  3. C small part of vas deferens is removed or tied up.
  4. D uterus is removed surgically.

Answer: A. small part of the fallopian tube is removed or tied up.

Why: Tubectomy is female sterilisation: a small part of each fallopian tube is cut or tied, blocking passage of the ovum. Cutting the vas deferens is vasectomy.

Question 170

Biology · Evolution

Forelimbs of cat, lizard used in walking; forelimbs of whale used in swimming and forelimbs of bats used in flying are an example of :-

  1. A Analogous organs
  2. B Adaptive radiation
  3. C Homologous organs
  4. D Convergent evolution

Answer: C. Homologous organs

Why: Forelimbs of cat, lizard, whale and bat share the same basic bone plan from a common ancestor but are modified for different functions, so they are homologous organs. (Adaptive radiation is also arguably defensible.)

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Frequently asked questions

How many questions were there in the AIPMT 2014 paper?

The AIPMT 2014 paper (Set P) in our collection has 180 questions: 90 in Biology, 45 in Physics and 45 in Chemistry. All 180 questions are compulsory.

What is the marking scheme of AIPMT 2014?

Each correct answer earns 4 marks and each wrong answer loses 1 mark. An unanswered question scores nothing.

Which chapters had the most questions in AIPMT 2014?

The chapters that carried the most questions were Biological Classification (9), Plant Kingdom (6), Sexual Reproduction in Flowering Plants (5).

Can I attempt the AIPMT 2014 paper online?

Yes. Open the AIPMT 2014 paper in the NeetVictory app, sit it under the real timing and marking, and see where you rank among students who have sat the same paper. Previous year papers are part of NeetVictory Pro.

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