Alcohols, Phenols and Ethers is a Class 12 Chemistry chapter that carries about 3.4% of the Chemistry questions in NEET. Practise it with 42 questions covering 2 topics, each with an explanation.
Sample questions on Alcohols, Phenols and Ethers with answers
8 questions from the practice bank, spread across the chapter's topics. The full set is in the app.
Question 1: Acidity of Phenols
Phenol gives a violet colour with neutral ferric chloride, which is used as:
- A a test for phenols
- B a test for amines
- C a test for aldehydes
- D a test for alcohols
Answer: A. a test for phenols
Why: The colour comes from a complex of Fe³⁺ with phenoxide.
Question 2: Preparation of Alcohols
The order of the boiling points of the isomeric butanols is:
- A tert-butanol > sec-butanol > n-butanol
- B sec-butanol > n-butanol > tert-butanol
- C n-butanol > sec-butanol > tert-butanol
- D all equal
Answer: C. n-butanol > sec-butanol > tert-butanol
Why: Branching reduces the surface area.
Question 3: Acidity of Phenols
On distilling with zinc dust, phenol gives:
- A benzene
- B toluene
- C cyclohexane
- D benzaldehyde
Answer: A. benzene
Why: The –OH group is removed.
Question 4: Preparation of Alcohols
In the Williamson synthesis, a good yield of an ether is obtained when sodium alkoxide reacts with:
- A a primary alkyl halide
- B a secondary alkyl halide only
- C a tertiary alkyl halide
- D an aryl halide
Answer: A. a primary alkyl halide
Why: The reaction is SN2; tertiary halides mainly undergo elimination to alkenes.
Question 5: Acidity of Phenols
p-Cresol is a weaker acid than phenol because the methyl group:
- A has no effect
- B donates electrons and destabilises the phenoxide ion
- C stabilises the phenoxide ion
- D withdraws electrons
Answer: B. donates electrons and destabilises the phenoxide ion
Why: Electron-donating groups decrease acidity.
Question 6: Preparation of Alcohols
The cleavage of tert-butyl methyl ether with HI gives mainly:
- A methanol and tert-butyl iodide, by an SN1 mechanism
- B only isobutene
- C methyl iodide and tert-butanol
- D no reaction
Answer: A. methanol and tert-butyl iodide, by an SN1 mechanism
Why: The tertiary carbocation is the more stable.
Question 7: Acidity of Phenols
Treating sodium phenoxide with carbon dioxide at high temperature and pressure, then acidifying, gives:
- A salicylaldehyde
- B benzoic acid
- C phenyl acetate
- D salicylic acid
Answer: D. salicylic acid
Why: This is the Kolbe reaction: electrophilic substitution of the phenoxide ring by CO₂.
Question 8: Preparation of Alcohols
Methanol is manufactured industrially by the catalytic hydrogenation of carbon monoxide:
- A CH₄ + O₂ → CH₃OH without a catalyst
- B CO + 2H₂ → CH₃OH, using ZnO–Cr₂O₃ at high pressure
- C CO₂ + H₂ → CH₃OH at room temperature only
- D C + H₂O → CH₃OH
Answer: B. CO + 2H₂ → CH₃OH, using ZnO–Cr₂O₃ at high pressure
Why: This is a key use of water gas.