A full-length NEET mock in the real pattern: 90 Biology, 45 Physics and 45 Chemistry questions, +4 for a correct answer and −1 for a wrong one. Mock 13 is the same paper for every student, so your rank is among everyone who sat it. Difficulty: 27% easy, 66% medium, 7% hard.
Sample questions from Mock 13 with answers
10 of the 180 questions, with answers and explanations. The rest are in the app.
Question 1
Biology · Cell: The Unit of LifeThe cell envelope of a bacterial cell consists of:
- A the cell wall only
- B the flagella and the pili
- C the nucleus and the cytoplasm
- D the glycocalyx, the cell wall and the plasma membrane
Answer: D. the glycocalyx, the cell wall and the plasma membrane
Why: The three layers function together as a single protective unit.
Question 2
Biology · Animal KingdomWhich of the following is a jawless vertebrate?
- A lizard
- B lamprey, Petromyzon
- C shark
- D frog
Answer: B. lamprey, Petromyzon
Why: The class is Cyclostomata.
Question 3
Biology · Reproductive HealthIUDs (intrauterine devices) such as Lippes loop work mainly by:
- A increasing phagocytosis of the sperms within the uterus, and making the uterus unsuitable for implantation
- B killing the ovum
- C removing the sperms from the vagina
- D blocking ovulation
Answer: A. increasing phagocytosis of the sperms within the uterus, and making the uterus unsuitable for implantation
Why: The hormone-releasing IUDs make the cervix hostile to sperms.
Question 4
Biology · Biotechnology: Principles and ProcessesDNA bands in an agarose gel are made visible by staining with:
- A ethidium bromide and exposure to UV light, which gives orange-coloured bands
- B methylene blue in daylight
- C iodine solution
- D Fehling's solution
Answer: A. ethidium bromide and exposure to UV light, which gives orange-coloured bands
Why: The separated bands are then cut out and eluted.
Question 5
Biology · Plant Growth and DevelopmentThe ethylene breaks the seed and bud dormancy, initiates the germination in the peanut seeds and the sprouting of the potato tubers. It also promotes the:
- A the stomatal closure
- B root growth and the root hair formation, which increases the absorption surface
- C the leaf fall only
- D the dormancy
Answer: B. root growth and the root hair formation, which increases the absorption surface
Why: It promotes the flowering in the mango and the pineapples.
Question 6
Physics · Thermal Properties of MatterA bimetallic strip of brass and iron is heated. It bends with the brass on the outer (convex) side because:
- A brass expands more than iron
- B both expand equally
- C brass contracts
- D iron expands more than brass
Answer: A. brass expands more than iron
Why: The metal with the larger α lengthens more and lies on the outside of the curve.
Question 7
Physics · Thermal Properties of MatterThe rate of conduction of heat through a rod of cross-sectional area A and length L, with a temperature difference ΔT across it and conductivity K, is:
- A KAL/ΔT
- B KAΔT/L
- C AΔT/KL
- D KΔT/AL
Answer: B. KAΔT/L
Why: This is the law of heat conduction.
Question 8
Chemistry · EquilibriumWhen the ratio of [salt]/[acid] in an acetic acid buffer is 10, the pH is (pKa = 4.76):
- A 4.76
- B 3.76
- C 5.76
- D 14.76
Answer: C. 5.76
Why: pH = 4.76 + log 10.
Question 9
Chemistry · Environmental ChemistryPhotochemical smog is characterised by high concentrations of:
- A CO and methane
- B ozone, PAN and aldehydes
- C CFCs
- D sulphur dioxide and soot
Answer: B. ozone, PAN and aldehydes
Why: It is formed from nitrogen oxides and hydrocarbons in sunlight.
Question 10
Chemistry · Aldehydes, Ketones and Carboxylic AcidsAlkaline hydrolysis of an ester (saponification) is irreversible because:
- A the carboxylic acid formed is converted to its salt, which cannot react with the alcohol
- B the ester is unstable
- C water is not needed
- D the alcohol is destroyed
Answer: A. the carboxylic acid formed is converted to its salt, which cannot react with the alcohol
Why: Acid hydrolysis is reversible.